Visual Basic (Declaration) | |
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Public Overloads Shared Function FrequencyTableOL( _ ByVal seriesName As String, _ ByVal s As Series, _ ByVal boundaries() As Double _ ) As Series |
Visual Basic (Usage) | Copy Code |
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C# | |
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public static Series FrequencyTableOL( string seriesName, Series s, double[] boundaries ) |
Parameters
- seriesName
- The name of the series which will be displayed on the chart, i.e. its label.
- s
- A statistical series.
- boundaries
- A strictly increasing sequence of boundaries of the intervals over the real line in which the data sets point will be assigned.
{b_1, b_2, ..., b_n}
, now the first term of the array returned which represents the frequency table, is the number of elements from the data set within the interval (-infinity, b_1)
, the second term of the array returned is the number of elements from the data set within the interval [b_1, b_2)
, and so on...
Example
Consider the set of boundaries { 1, 2, 3, 4, 5 }
, which divide the real line into six sub-intervals. Now if we use the open left boundary convention then the real line will be divided into the sub-intervals:
(-infinity, 1], (1,2], (2,3], (3,4], (4,5], (5, infinity)
Note that, each point on the real line can be assigned to one of these sub-intervals and therefore when assigning a data point to one of these intervals there will only be one sub-interval in which it belongs.
Therefore, if we consider the data set { 0.5, 1.4, 1.3, 2.0, 2.3, 4.5, 5.5}
, if the assign this data set in accordance with the above the conventions then we will have: using Open Left Boundary (OLB) convention:
- Within the interval
(-infinity, 1]
, we assign the data element0.5
; and hence the frequency of this interval is1
. - Within the interval
(1, 2]
, we assign the data element1.4, 1.3, 2.0
; and hence the frequency of this interval (wrt OLB convention) is3
. - Within the interval
(2, 3]
, we assign the data element2.3
, and hence the frequency of this interval (wrt OLB convention) is1
. - Within the interval
(3, 4]
, we assign no data elements, and hence the frequency of this interval (wrt OLB convention) is0
. - Within the interval
(4, 5]
, we assign the data element4.5
, and hence the frequency of this interval (wrt OLB convention) is1
. - Within the interval
(5, infinity)
, we assign the data element5.5
, and hence the frequency of this interval (wrt OLB convention) is1
.
Hence, in this case the series returned corresponding to the frequency table will be {1, 3, 1, 0, 1, 1}
.